0,1x^2+0,03=0,04

Solution for 0,1x^2+0,03=0,04 equation:

0.1x^2+0.03=0.04

We move all terms to the left:

0.1x^2+0.03-(0.04)=0

We add all the numbers together, and all the variables

0.1x^2-0.01=0

a = 0.1; b = 0; c = -0.01;
Δ = b2-4ac
Δ = 02-4·0.1·(-0.01)
Δ = 0.004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.004}}{2*0.1}=\frac{0-\sqrt{0.004}}{0.2}
=-\frac{\sqrt{}}{0.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.004}}{2*0.1}=\frac{0+\sqrt{0.004}}{0.2}
=\frac{\sqrt{}}{0.2}
$